7 runs were needed from 1 ball… Indian batsman was in front, hit a six, still the team lost

New Delhi. In the 2019 IPL, when the teams of Sunrisers Hyderabad and Mumbai Indians were face to face, an amazing match took place. In the 51st match of IPL 2019, Sunrisers Hyderabad needed 163 runs to win. He was successful in scoring 162 runs. But the match was lost. Manish Pand had tied the match by hitting a six. But Hardik made his team in bad condition in the super over.

Batting first, Mumbai Indians had scored 162 runs. Hyderabad needed 163 runs to win. Hyderabad lost its initial wickets very quickly. After this Manish Pandey came to bat. Manish batted brilliantly and took the team closer to victory. Now the match came to such a stage that Hyderabad needed 7 runs in 1 ball to win. The ball was in the hands of Hardik Pandya from Mumbai.

Manish Pandey hit a brilliant six on the last ball of Hardik Pandya's 20th over and tied the match. But he could not win the match. Pandey played an inning of 71 runs in 47 balls in this match. The score of both the teams became 162-162 and the match was tied. Now in such a situation the turn of super over has come. Hardik Pandya from Mumbai became the call for Sunrisers Hyderabad in the Super Over.

Hyderabad team came to bat first in the Super Over. Manish Pandey and Mohammad Nabi were out and the team could score only 8 runs at the loss of 2 wickets. Now MI needed only 9 runs to win. Hardik Pandya, who came for Mumbai, hit a six on the very first ball. After this gave a single to Pollard. Pollard gave the team victory by taking 2 runs on the third ball and Sunrisers Hyderabad lost.